SOLUTION: 2 cars race around a circular track, in opposite directions, at constant speeds. They start at the same point and meet every 30.0 seconds. If they move in the same direction, they

Algebra ->  Trigonometry-basics -> SOLUTION: 2 cars race around a circular track, in opposite directions, at constant speeds. They start at the same point and meet every 30.0 seconds. If they move in the same direction, they      Log On


   



Question 156483: 2 cars race around a circular track, in opposite directions, at constant speeds. They start at the same point and meet every 30.0 seconds. If they move in the same direction, they meet every 120.0 seconds. If the track is 1800 meters long, what is the speed of each car?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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2 cars race around a circular track, in opposite directions, at constant speeds.
They start at the same point and meet every 30.0 seconds. If they move in the
same direction, they meet every 120.0 seconds. If the track is 1800 meters
long, what is the speed of each car?
:
Change seconds to min in the problem
:
Let a = speed of car a (in meters/min)
Let b = speed of car b
:
.5(a+b) = 1800
Multiply equation by 2
a + b = 3600
:
2(a-b) = 1800
Divide both sides by 2
a - b = 900
:
a + b = 3600
a - b = 900
--------------adding eliminates b
2a = 4500
a = 4500%2F2
a = 2250 meters/min (%282250%2A60%29%2F1000 = 135 km/hr)
:
Find the speed of b
a + b = 3600
a + 2250 = 3600
a = 3600 - 2250
a = 1350 meters/min (%281350%2A60%29%2F1000 = 81 km/hr)