SOLUTION: What is the slope of the line whose equation is 3x-4y-16-0? work: 3x-4y-16=0 -3x -3x -4y=-3x+16 \-4 \-4 y=-3x+16\4

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: What is the slope of the line whose equation is 3x-4y-16-0? work: 3x-4y-16=0 -3x -3x -4y=-3x+16 \-4 \-4 y=-3x+16\4      Log On


   

Question 156477: What is the slope of the line whose equation is 3x-4y-16-0?

work:
3x-4y-16=0
-3x -3x
-4y=-3x+16
\-4 \-4
y=-3x+16\4
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
Regarding:
work:
3x-4y-16=0
-3x -3x
-4y=-3x+16 <<--so far, so good!
\-4 \-4
y=-3x+16\4 <<--you forgot to divide the first term on the right (and neg)
.
Should be:
3x-4y-16=0
-4y=-3x+16
y=(-3/-4)x + 16\(-4)
y=(3/4)x - 4
Slope is 3/4