SOLUTION: I have been struggling on this problem for awhile now and I was wondering if someone could help me? I would deeply appreciate it. Please and Thank you!!
The telephone company of
Algebra ->
Customizable Word Problem Solvers
-> Misc
-> SOLUTION: I have been struggling on this problem for awhile now and I was wondering if someone could help me? I would deeply appreciate it. Please and Thank you!!
The telephone company of
Log On
Question 156247This question is from textbook Algebra and Trigonometry Structure and Method book 2
: I have been struggling on this problem for awhile now and I was wondering if someone could help me? I would deeply appreciate it. Please and Thank you!!
The telephone company offers two types of service. With Plan A, you can make an unlimited number of local calls per month for $18.50. With Plan B, you pay $6.50 monthly, plus 10 cents for each min of calls after the first 40 min. At least how many min would you have to use the telephone each month to make Plan A the better option? This question is from textbook Algebra and Trigonometry Structure and Method book 2
You can put this solution on YOUR website! The telephone company offers two types of service. With Plan A, you can make an unlimited number of local calls per month for $18.50. With Plan B, you pay $6.50 monthly, plus 10 cents for each min of calls after the first 40 min. At least how many min would you have to use the telephone each month to make Plan A the better option?
:
Let m = no. of minutes used
:
PlanA cost = 18.50
:
PlanB cost = .10(m-40) + 6.50
:
PlanB > PlanA
.10(m-40) + 6.50 > 18.50
:
.10m - 4 + 6.50 > 18.50
:
.10m + 2.50 > 18.50
:
.10m > 18.50 - 2.50
:
.10m > 16.00
m >
m > 160 minutes
:
We can say if you exceed 160 min, PlanA is the better deal
:
Check this using 161 min in PlanB
C = .10(161-40) + 6.50
C = .10(121) + 6.50
C = 12.10 + 6.50
C = 18.60, ten cents more than PlanA
