SOLUTION: Please help me solve this problem:: There is $65.00 in dimes and quarters. If there is 389 coins how many were dimes and how many were quarters?

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Question 156220: Please help me solve this problem::
There is $65.00 in dimes and quarters. If there is 389 coins how many were dimes and how many were quarters?

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
There is $65.00 in dimes and quarters. If there is 389 coins how many were dimes and how many were quarters?
:
d + q = 389
d = (389-q)
:
.10d + .25q = 65
:
.10(389-q) + .25q = 65
:
38.9 - .10q + .25q = 65
:
.15q = 65 - 38.9
:
.15q = 26.1
q = 26.1%2F.15
q = 174 quarters
:
d = 389 - 174
d = 215 dimes
:
:
Check solutions
.10(215) + .25(174) =
21.5 + 43.5 = 65.00