SOLUTION: CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM: What is g(x) = f^-1(x) if f(x) = 1/2 x? a. g(x) = 0 b. g(x) = -2x c. g(x) = 1/2x^-1 d. g(x) = 2x

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM: What is g(x) = f^-1(x) if f(x) = 1/2 x? a. g(x) = 0 b. g(x) = -2x c. g(x) = 1/2x^-1 d. g(x) = 2x      Log On


   

Question 156161: CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM:
What is g(x) = f^-1(x) if f(x) = 1/2 x?
a. g(x) = 0
b. g(x) = -2x
c. g(x) = 1/2x^-1
d. g(x) = 2x
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Is the function f%28x%29=%281%2F2%29x ?


f%28x%29=%281%2F2%29x Start with the given expression


y=%281%2F2%29x Replace f%28x%29 with "y"


x=%281%2F2%29y Switch "x" and "y"


2x=y Multiply both sides by 2 to solve for "y"


So after solving for "y", we get y=2x. So the inverse function is


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Or...

Is the function f%28x%29=%281%29%2F%282x%29 ?


f%28x%29=%281%29%2F%282x%29 Start with the given expression


y=%281%29%2F%282x%29 Replace f%28x%29 with "y"


x=%281%29%2F%282y%29 Switch "x" and "y"


2xy=1 Multiply both sides by 2y


y=1%2F%282x%29 Divide both sides by 2x to solve for "y"


So after solving for "y", we get y=1%2F%282x%29. So the inverse function is