SOLUTION: The length of a rectangle is 7 inches less than 3 times its width. If the perimeter of the rectangle is 50 inches, what are its dimensions? 7-3x=50 is what I came up with but

Algebra ->  Human-and-algebraic-language -> SOLUTION: The length of a rectangle is 7 inches less than 3 times its width. If the perimeter of the rectangle is 50 inches, what are its dimensions? 7-3x=50 is what I came up with but       Log On


   

Question 156029: The length of a rectangle is 7 inches less than 3 times its width. If the perimeter of the rectangle is 50 inches, what are its dimensions?

7-3x=50 is what I came up with but I do not believe that this is how to solve it but before I did it I just wanted some help I am taking a class online and can't ask the teacher.
Thank You
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
"The length of a rectangle is 7 inches less than 3 times its width" __ L=3W-7

"the perimeter of the rectangle is 50 inches" __ 2L+2W=50

substituting __ 2(3W-7)+2W=50 __ 6W-14+2W=50 __ 8W=64 __ W=8

substituting __ L=3(8)-7 __ L=17