SOLUTION: a ticket master sold 480 tickets. the floor tickets were $30 each and upper $24 each. they made $13,200. how many of each ticket did they sell?

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: a ticket master sold 480 tickets. the floor tickets were $30 each and upper $24 each. they made $13,200. how many of each ticket did they sell?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 156006: a ticket master sold 480 tickets. the floor tickets were $30 each and upper $24 each. they made $13,200. how many of each ticket did they sell?
Found 2 solutions by checkley77, stanbon:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
X+Y=480
X=480-Y
30X+24Y=13,200
30(480-Y)+24Y=13,200
14,400-30Y+24Y=13,200
-6Y=13,200-14,400
-6Y=-1,200
Y=-1,200/-6
Y=200 24 DOLLAR TICKETS SOLD.
480-200=280 30 DOLLAR TICKETS SOLD.
PROOF;
30*280+24*200=13,200
8,400+4,800=13,200
13,200=13,200

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
a ticket master sold 480 tickets. the floor tickets were $30 each and upper $24 each. they made $13,200. how many of each ticket did they sell?
-------------------
One-Variable Solution:
Value EQUATION: 30x + 24(480-x) = 13200, where x is the number of floor tickets.
30x + 24*480 - 24x = 13200
6x = 1680
x = 280 (# of floor tickets sold)
480-x = 200 (# of upper tickets)
=======================
Cheers,
Stan H.