Question 155990: y^2=x+1. Find the vertex, x and y intercepts, and sketch the graph. Please help, I have no idea what to do with this!!!
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! y^2=x+1. Find the vertex, x and y intercepts, and sketch the graph.
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(y-0)^2 + 4(1/4)(x+1)
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Vertex: (-1,0)
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x-intercept: Let y = 0, then x+1 = 0; x = -1
x-intercept: (-1,0)
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y-intercept: Let x = 0, then y^2 = 1; y = +/-1
y-intercepts: (0,1) and (0,-1)
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Graph:
x = y^2-1
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Plot the vertex at (-1,0)
Plot the y-intercepts at (0,1) and (0,-1)
The graph is a parabola opening to the right.
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Cheers,
Stan H.
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