SOLUTION: How many pounds of an alloy containing 32% silver must be melted with 25 pounds of an alloy containing 48% silver to obtain and alloy containing 42% silver?
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Question 155816: How many pounds of an alloy containing 32% silver must be melted with 25 pounds of an alloy containing 48% silver to obtain and alloy containing 42% silver? Answer by ptaylor(2198) (Show Source):
You can put this solution on YOUR website!
Let x=amount of 32% silver alloy needed
Now we know that the amount of pure silver in the 32% alloy (0.32x) plus the amount of pure silver in the 48% alloy (0.48*25) has to equal the amount of pure silver in the final mixture(0.42*(25+x)). So our equation to solve is:
0.32x+0.48*25=0.42(25+x) get rid of parens and simplify
0.32x+12=10.5+0.42x subtract 0.32x and also 10.5 from each side
0.32x-0.32x+12-10.5=10.5-10.5+0.42x-0.32x collect like terms
0.10x=1.5 divide each side by 0.10
x=15 lb----------------------------amount of 32% silver alloy needed
CK
0.32*15+0.48*25=0.42*40
4.8+12=16.8
16.8=16.8
Hope this helps----ptaylor
