SOLUTION: Find an equation of the line containing the given pair of points. Express your answer in the form x=a, y=b, or y=mx+b. (-2,-2) and (1,1)

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Find an equation of the line containing the given pair of points. Express your answer in the form x=a, y=b, or y=mx+b. (-2,-2) and (1,1)       Log On


   

Question 155725: Find an equation of the line containing the given pair of points. Express your answer in the form x=a, y=b, or y=mx+b.
(-2,-2) and (1,1)
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
fIRST WE FIND THE SLOPE:
SLOPE=(Y2-Y1)/(X2-X1)
SLOPE=(1+2)/(1+2)
SLOPE=3/3=1
Y=mX+b
1=1*1+b
1=1+b
b=1-1
b=0
y=x is the line equation through these 2 points.
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+x%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = x).