SOLUTION: Find the horizontal asymptote, if any, of the graph of the rational function.
{{{g(x)=(6x^2)/(2x^2+1)}}}
a){{{y=3}}}
b){{{y=1/3}}}
c){{{y=0}}}
d){{{no_horizontal_asymptote}}
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: Find the horizontal asymptote, if any, of the graph of the rational function.
{{{g(x)=(6x^2)/(2x^2+1)}}}
a){{{y=3}}}
b){{{y=1/3}}}
c){{{y=0}}}
d){{{no_horizontal_asymptote}}
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Rules for horizontal asymptotes:
1. If the largest exponent of x in the numerator is GREATER than the
largest exponent of x in the denominator, there is
.
2. If the largest exponent of x in the numerator is LESS than the
largest exponent of x in the denominator, the horizontal asymptote is the
x-axis, whose equation is
3. If the largest exponent of x in the numerator is EQUAL to the
largest exponent of x in the denominator, the horizontal asymptote is
horizontal line whose equation is
---------------------
In your function:
the largest exponent of x in the numerator is 2, and
the largest exponent of x in the denominator is also 2.
They are equal so we use rule 3:
the horizontal asymptote is
horizontal line whose equation is
The coefficient of the largest exponent of x in the numerator is
6, and the coefficient of the largest exponent of x in the
denominator is 2, so the horizontal asymptote is the line
whose equation is:
So the correct choice is (a)
Edwin