SOLUTION: write an equation that expresses the relationship. Use k as the constant of variation.
d varies directly as the square of y
a) d= k sqrt y
b) d= k/sqrt y
c) d= ky^2
d
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: write an equation that expresses the relationship. Use k as the constant of variation.
d varies directly as the square of y
a) d= k sqrt y
b) d= k/sqrt y
c) d= ky^2
d
Log On
Question 155653: write an equation that expresses the relationship. Use k as the constant of variation.
d varies directly as the square of y
a) d= k sqrt y
b) d= k/sqrt y
c) d= ky^2
d) d= k/ y^2 Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! write an equation that expresses the relationship. Use k as the constant of variation.
d varies directly as the square of y
a) d= k sqrt y
b) d= k/sqrt y
c) d= ky^2
d) d= k/ y^2
-----------
It's c) d = ky^2
That's the only one that is a function of y^2. d has y^2, but in the denominator it is y^(-2), so that's eliminated, or that would be called "varies inversely as the square of y"