SOLUTION: write an equation that expresses the relationship. Use k as the constant of variation. d varies directly as the square of y a) d= k sqrt y b) d= k/sqrt y c) d= ky^2 d

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: write an equation that expresses the relationship. Use k as the constant of variation. d varies directly as the square of y a) d= k sqrt y b) d= k/sqrt y c) d= ky^2 d      Log On


   



Question 155653: write an equation that expresses the relationship. Use k as the constant of variation.
d varies directly as the square of y
a) d= k sqrt y
b) d= k/sqrt y
c) d= ky^2
d) d= k/ y^2

Answer by Alan3354(69443) About Me  (Show Source):
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write an equation that expresses the relationship. Use k as the constant of variation.
d varies directly as the square of y
a) d= k sqrt y
b) d= k/sqrt y
c) d= ky^2
d) d= k/ y^2
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It's c) d = ky^2
That's the only one that is a function of y^2. d has y^2, but in the denominator it is y^(-2), so that's eliminated, or that would be called "varies inversely as the square of y"