SOLUTION: Tickets for a concert were sold to adults for $3 and to students for $2. If the total receipts were $824 and twice as many adult tickets as student tickets were sold, then how m

Algebra ->  Linear-equations -> SOLUTION: Tickets for a concert were sold to adults for $3 and to students for $2. If the total receipts were $824 and twice as many adult tickets as student tickets were sold, then how m      Log On


   

Question 155651This question is from textbook Elementary and Intermediate Algebra
: Tickets for a concert were sold to adults for
$3 and to students for $2. If the total receipts were $824
and twice as many adult tickets as student tickets were
sold, then how many of each were sold?
 This question is from textbook Elementary and Intermediate Algebra

Found 2 solutions by oscargut, checkley77:
Answer by oscargut(2103) About Me  (Show Source):
You can put this solution on YOUR website!
x=number of adults tickets
y=number of students tickets
Tickets for a concert were sold to adults for
$3 and to students for $2,total receipts were $824
then 3x+2y=824
twice as many adult tickets as student tickets were
sold,
then x=2y
then
3x%2B2y=824
x=2y
then
3%282y%29%2B2y=824
then
8y=824
then
y=103
x=206

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
A=2S
A*3+2S=824
3(2S)+2S=824
6S+2S=824
8S=824
S=103 STUDENT TICKETS SOLD.
A=2*103=206 ADULT TICKETS SOLD
PROOF:
206*3+103*2=824
618+206=824
824=824