Question 155581: How many gallons of a 60% antifreeze solution must be mixed with 100 gallons of 15% antifreeze to get a mixture that is 50% antifreeze? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How many gallons of a 60% antifreeze solution must be mixed with 100 gallons of 15% antifreeze to get a mixture that is 50% antifreeze?
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Amt of 60% solution = x gallons ; Amt of active ingredient = 0.6x gallons
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Amt of 15% solution = 100 gallons ; Amt of active ingredient = 15 gallons
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Amt of 50% solution = 100+x gallons ; Amt of active = 50 + 0.5x gallons
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EQUATION:
Active ingredient: 0.60x + 15 = 50 + 0.50x
0.10x = 35
x = 350 gallons (amt of 60% solution that must be added)
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Cheers,
Stan H.