SOLUTION: HELP!!! Questions: You have invested $5,000,000.00 to add new rides to an amusement park. How many park visitors would have to come on a daily basis for 1 season (1 season =6

Algebra ->  Human-and-algebraic-language -> SOLUTION: HELP!!! Questions: You have invested $5,000,000.00 to add new rides to an amusement park. How many park visitors would have to come on a daily basis for 1 season (1 season =6       Log On


   



Question 15558: HELP!!!
Questions: You have invested $5,000,000.00 to add new rides to an amusement park. How many park visitors would have to come on a daily basis for 1 season (1 season =6 months) to recoup the $5,000,000 over 20 years? The average per person ticket cost is $35.00 per day.
Can you help me translate this into an algebraic equation????
I don't know where to begin...
I would appreciate any help!
Ashley

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
You have invested $5,000,000.00 to add new rides to an amusement park. How many park visitors would have to come on a daily basis for 1 season (1 season =6 months) to recoup the $5,000,000 over 20 years? The average per person ticket cost is $35.00 per day.
Can you help me translate this into an algebraic equation????
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Let "x" be the number of daily park visitors.
EQUATION:
6 months is 365/2 days
So years of 6 month seasons =20(365/2)=3650 days
Each person with a daily pass would pay $35
EQUATION:
3650(35)x=5,000,000
x=39.13 people.
Since people don't come in fractional parts you
would need to have 40 people attend daily for
6 months per/yr for 20 years to take in $5 million dollars.
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Cheers,
Stan H.