SOLUTION: we are discussing factoring and we have to solve these problems. 1. (2x - 3)(x - 4) = 0 2. x^2 + 3x - 28 = 0 3. x^2 + 16 = -10x

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: we are discussing factoring and we have to solve these problems. 1. (2x - 3)(x - 4) = 0 2. x^2 + 3x - 28 = 0 3. x^2 + 16 = -10x       Log On


   

Question 155491This question is from textbook elementary and intermediate algebra
: we are discussing factoring and we have to solve these problems.
1. (2x - 3)(x - 4) = 0
2. x^2 + 3x - 28 = 0
3. x^2 + 16 = -10x
This question is from textbook elementary and intermediate algebra

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
1. (2x - 3)(x - 4) = 0
2X-3=0
2X=3
X=3/2 ANSWER.
X-4=0
X=4 ANSWER.
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2. x^2 + 3x - 28 = 0
(X+7)(X-3)=0
X+7=0
X=-7 ANSWER.
X-3=0
X=3 ANSWER.
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3. x^2 + 16 = -10x
X^2+10X+16=0
(X+8)(X+2)=0
X+8=0
X=-8 ANSWER.
X+2=0
X=-2 ANSWER.