SOLUTION: A man has an outdoor patio connected to his coffee shop. His plans call for a 42 inch high brick wall that will surround three sides of the patio with the coffee shop as the fourth

Algebra ->  Functions -> SOLUTION: A man has an outdoor patio connected to his coffee shop. His plans call for a 42 inch high brick wall that will surround three sides of the patio with the coffee shop as the fourth      Log On


   

Question 155486: A man has an outdoor patio connected to his coffee shop. His plans call for a 42 inch high brick wall that will surround three sides of the patio with the coffee shop as the fourth wall. He found someone to sell him molding but there is obly enough for 80 feet. he wants atleast 10 outdoor patio tables which each take up 64 square foot. He needs to consider the floor area of the patio.
What would be the equation for this word problem?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
10*64=640 FT^2 FOR THE PATIO.
2X+Y=80 FOR THE PERIMETER.
XY=640
Y=640/X
2X+640/X=80
(2X^2+640)/X=80
2X^2+640=80X
2X^2-80X+640=0
2(X^2-40X+320)=0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
X=(40+-SQRT[-40^2-4*1*320])/2*1
X=(40+-SQRT1600-1280])/2
X=(40+-SQRT320)/2
X=(40+-17.89)/2
X=(40+17.89)/2
X=57.89/2
X=28.945 FT. ANSWER.
2*28.945+Y=80
57.89+Y=80
Y=80-57.89
Y=22.11 FT. ANSWER.
DIMENTIONS FOR THE WALL ARE:2 WALLS=28.945 FT. EACH & THE THIRD WALL IS 22.11 FT.
PROOF:
28.945*22.11=640
640=640