SOLUTION: Write the equation in its equivalent logarithmic form. 5-2 = 1 / 25 log5-2 = 1 / 25 log 1/5 5 = -2 log5 1 / 25 = -2 log-2 1 / 2

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Write the equation in its equivalent logarithmic form. 5-2 = 1 / 25 log5-2 = 1 / 25 log 1/5 5 = -2 log5 1 / 25 = -2 log-2 1 / 2      Log On


   

Question 155465: Write the equation in its equivalent logarithmic form.
5-2 = 1 / 25


log5-2 = 1 / 25


log 1/5 5 = -2


log5 1 / 25 = -2


log-2 1 / 25 = 5
Answer by oscargut(2103) About Me  (Show Source):
You can put this solution on YOUR website!
in gral
b%5E%28c%29=a if only if log+b%28a%29=c
5%5E%28-2%29=1%2F25 if only if log5%281%2F25%29=-2
so correct option is the third