SOLUTION: Katy leaves City A for City B at 7 am. driving a 51 mph. at 10am Jensen leaves City B for City A driving at 60 mph. If the cities are 264 miles apart at what time will they meet?
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Question 155432: Katy leaves City A for City B at 7 am. driving a 51 mph. at 10am Jensen leaves City B for City A driving at 60 mph. If the cities are 264 miles apart at what time will they meet? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Katy leaves City A for City B at 7 am. driving a 51 mph. at 10am Jensen leaves City B for City A driving at 60 mph. If the cities are 264 miles apart at what time will they meet?
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Katy DATA:
rate = 51 mph ; time = x hrs. ; distance = 51x miles
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Jensen DATA:
rate = 60 mph ; time = x-3 hrs ; distance = 60(x-3) miles
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EQUATION:
51x + 60x-180 = 264
111x = 444
x = 4 hours
They will meet at 7 am + 4 hrs = 11 am
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Cheers,
Stan H.
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