Question 155385: Please help me to solve this problem.I really don`t understand and drastically need help. Thank you so much for all that you do! Please help me! Here is the problem:
Tommy has 40 coins(all nickels, dimes, and quarters) worth 4.50. He has 7 more nickels than dimes. How many quarters does Tommy have? Write an equation.
Thanks again so much for the help!
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Tommy has 40 coins(all nickels, dimes, and quarters) worth 4.50. He has 7 more nickels than dimes. How many quarters does Tommy have? Write an equation.
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Let # of dimes be "x"; Value of these is 10x cents
Number of nickels is "x+7" ; Value of these is 5(x+7) = 5x+35 cents
Number of quarters is 40 - x - (x+7)= 33-2x ; Value = 25(33-2x)= 825-50x cents
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EQUATION:
value + value + value = 450 cents
10x + 5x + 35 + 825 - 50x = 450
-35x + 860 = 450
-35x = -410
x = 11.71
Note: The solution should be a whole number as it
is the number of dimes.
Check your problem statement.
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Cheers,
Stan H.
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