SOLUTION: Mr. Newton drives to and from work over the same route each day. On Friday, he drives at an average rate of 52 km/hr and is one minute late to work. ON Monday, he drives at an av

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Question 155283: Mr. Newton drives to and from work over the same route each day. On Friday, he drives at an average rate of 52 km/hr and is one minute late to work. ON Monday, he drives at an average rate of 60 km/hr and is one minute early to work. If he left home at the same time each day, what is the distance Mr. Newton travels from home (one way) to work.
Not from a text book, it was on a sheet of paper. thankyou.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
D=RT
D=52(T+1/60)
D=60(T-1/60)
52(T+1/60=60(T-1/60)
52T+52/60=60T-60/60
52T-60T=(-52-60)/60
-8T=-112/60
T=-112/60*-1/8
T=112/480
T=.23333 IS HIS TRAVEL TIME
D=60(.2333-1/60)
D=60(60*.2333-1)/60
D=60(14-1)/60
D=60*13/60
D=13 KM. IS HIS DRIVING DISTANCE.
PROOF:
13=52(.2333+1)/60
13=52(60*.2333+1)/60
13=52(14+1)/60
13=52*15/60
13=780/60
13=13