SOLUTION: How many solutions exist for a quadratic equation? How do we determine whether the solutions are real or complex?

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Question 155144: How many solutions exist for a quadratic equation? How do we determine whether the solutions are real or complex?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

A quadratic polynomial can have 2 real solutions, 1 real solution, or 2 complex solutions. To determine whether the solutions are real or complex, simply use the discriminant formula.

For example, to see if the equation 2x%5E2%2B6x-10 has real or complex solutions, let's use the discriminant formula



From 2x%5E2%2B6x-10 we can see that a=2, b=6, and c=-10


D=b%5E2-4ac Start with the discriminant formula.


D=%286%29%5E2-4%282%29%28-10%29 Plug in a=2, b=6, and c=-10


D=36-4%282%29%28-10%29 Square 6 to get 36


D=36--80 Multiply 4(2)(-10) to get (8)(-10)=-80


D=36%2B80 Rewrite D=36--80 as D=36+80


D=116 Add 36 to 80 to get 116


Since the discriminant is greater than zero, this means that there are two real solutions. So the quadratic has two real solutions