SOLUTION: The level of thorium in a sample decreases by a factor of one-half every 4.2 million years. A meteorite is discovered to have only 7.6% of it's original thorium remaining. How ol
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-> SOLUTION: The level of thorium in a sample decreases by a factor of one-half every 4.2 million years. A meteorite is discovered to have only 7.6% of it's original thorium remaining. How ol
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Question 155032: The level of thorium in a sample decreases by a factor of one-half every 4.2 million years. A meteorite is discovered to have only 7.6% of it's original thorium remaining. How old is the meteorite? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! The level of thorium in a sample decreases by a factor of one-half every 4.2 million years. A meteorite is discovered to have only 7.6% of it's original thorium remaining. How old is the meteorite?
:
The half-life formula:
A = Ao*2^(-t/h)
where:
Ao = initial amt (= 1 in this problem)
A = resulting amt (decimal equiv of %)
t = time (in millions of years here)
h = half-life of the substance (millions of years)
:
.076 = 1*2^(-t/4.2)
or
2^(-t/4.2) = .076
:
Find the nat log of both sides: *.693147 = -2.577022
: =
Cross multiply:
-.693147t = 4.2 * -2.577022
:
-.693147t = -10.8235
t = ; (minus into a minus is plus)
t = 15.615 million years old
:
:
Check solution on a calc: enter 2^(-15.615/4.2) = .075999 ~ .076 or 7.6%
