SOLUTION: can you please help me solve this problem and show all work using the 5-step method: (((A sailboat travels 20 miles downstream in 3 hours. It returns in 4 hours. Find the speed of

Algebra ->  Exponents-negative-and-fractional -> SOLUTION: can you please help me solve this problem and show all work using the 5-step method: (((A sailboat travels 20 miles downstream in 3 hours. It returns in 4 hours. Find the speed of       Log On


   

Question 154657This question is from textbook Algebra structure and method book 1
: can you please help me solve this problem and show all work using the 5-step method: (((A sailboat travels 20 miles downstream in 3 hours. It returns in 4 hours. Find the speed of the sailboat in still water and the rate of the current.))) This question is from textbook Algebra structure and method book 1

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
DISTANCE=RATE*TIME OR DISTANCE/TIME=RATE
20/3=6.666 WITH THE CURRENT.
20/4=5 AGAINST THE CURRENT.
(6.666-5)/2=1.666/2=.833MPH IS THE SPEED OF THE CURRENT.
PROOF:
6.666-.833=5.833 SPEED OF THE SAIL BOAT.
5+.833=5.833 DITTO.