SOLUTION: The width of a rectangular box is 4 times its height, and its length is 3 ft more than its height. The volume of the box is 49 ft cube. Find the height of the box.
volume = lwh
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-> SOLUTION: The width of a rectangular box is 4 times its height, and its length is 3 ft more than its height. The volume of the box is 49 ft cube. Find the height of the box.
volume = lwh
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Question 154586: The width of a rectangular box is 4 times its height, and its length is 3 ft more than its height. The volume of the box is 49 ft cube. Find the height of the box.
volume = lwh
49 = (4x)(3+x)(x)
49 = 4x3 +12x2 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The width of a rectangular box is 4 times its height, and its length is 3 ft more than its height. The volume of the box is 49 ft cube. Find the height of the box.
volume = lwh
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Let the height be "x":
width = 4x
length = x+3
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EQUATION:
V = lwh
49 = x*4x*(x+3)
49 = 4x^3 + 12x^2
4x^3 + 12x^2 - 49 = 0
I graphed it and found:
x = 1.627098...ft (height
4x = 6.508392
x+3= 4.627
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Cheers,
Stan H.
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