SOLUTION: Remember to isolate the absolute value. |x | = 6 |3x + 2| = 14 - 5| x + 1| = -10 |x - 2| + 10 = 12 |x| = - 5 |2x + 6| - 4 = 20 6 - 3|2x + 6| = 0

Algebra ->  Absolute-value -> SOLUTION: Remember to isolate the absolute value. |x | = 6 |3x + 2| = 14 - 5| x + 1| = -10 |x - 2| + 10 = 12 |x| = - 5 |2x + 6| - 4 = 20 6 - 3|2x + 6| = 0       Log On


   

Question 154544: Remember to isolate the absolute value.
|x | = 6

|3x + 2| = 14

- 5| x + 1| = -10

|x - 2| + 10 = 12

|x| = - 5

|2x + 6| - 4 = 20

6 - 3|2x + 6| = 0

10 - |x + 2| = 12

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
To solve these:
1) Get everything not in the absolute sign on the right side of the equal sign.
2) Solve the equation.
3) Multiply everything on the right side of the equal sign by -1.
4) Solve that equation.
.
|2x + 6| - 4 = 20
|2x+6|=24
2x+6=24
2x=18
x=9
.
|2x+6|=24
2x+6=-24
2x=-30
x=-15
.
.
6 - 3|2x + 6| = 0
-3|2x+6|=-6
|2x+6|=2
2x+6=2
2x=-4
x=-2
.
|2x+6|=2
2x+6=-2
2x=-8
x=-4
.
.
10 - |x + 2| = 12
-|x+2|=2
|x+2|=-2
An absolute cannot be negative. There is no answer.
.
Ed