SOLUTION: Find an equation of the line containing the given pair of points (-6,0)(0,1)

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Question 154337: Find an equation of the line containing the given pair of points
(-6,0)(0,1)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

First let's find the slope of the line through the points and


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%281-0%29%2F%280--6%29 Plug in y%5B2%5D=1, y%5B1%5D=0, x%5B2%5D=0, and x%5B1%5D=-6


m=%281%29%2F%280--6%29 Subtract 0 from 1 to get 1


m=%281%29%2F%286%29 Subtract -6 from 0 to get 6


So the slope of the line that goes through the points and is m=1%2F6


Now let's use the point slope formula:


y-y%5B1%5D=m%28x-x%5B1%5D%29 Start with the point slope formula


y-0=%281%2F6%29%28x--6%29 Plug in m=1%2F6, x%5B1%5D=-6, and y%5B1%5D=0


y-0=%281%2F6%29%28x%2B6%29 Rewrite x--6 as x%2B6


y-0=%281%2F6%29x%2B%281%2F6%29%286%29 Distribute


y-0=%281%2F6%29x%2B1 Multiply


y=%281%2F6%29x%2B1%2B0 Add 0 to both sides.


y=%281%2F6%29x%2B1 Combine like terms.



So the equation that goes through the points and is y=%281%2F6%29x%2B1


Notice how the graph of y=%281%2F6%29x%2B1 goes through the points and . So this visually verifies our answer.
Graph of y=%281%2F6%29x%2B1 through the points and