SOLUTION: A large pump can fill a 54,000 gallon reservoir in 8 hours. Working together, the largepump and a smaller one can fill the reservoir in 6 hours. How long would it take the smaller

Algebra ->  Rate-of-work-word-problems -> SOLUTION: A large pump can fill a 54,000 gallon reservoir in 8 hours. Working together, the largepump and a smaller one can fill the reservoir in 6 hours. How long would it take the smaller       Log On


   

Question 154302: A large pump can fill a 54,000 gallon reservoir in 8 hours. Working together, the largepump and a smaller one can fill the reservoir in 6 hours. How long would it take the smaller pump to fill the reservoir by itself?

Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!
Remember:
LargePump=highlight%28LP%29=54000gal%2F8hrs ----> condition 1
SmallPump=highlight%28SP%29=unknown
But, LP%2BSP=54000gal%2F6hrs ---------------> condition 2
Substitute condtn. 1 in condtn. 2:
%2854000%2F8%29%2BSP=54000%2F6
SP=%2854000%2F6%29-%2854000%2F8%29. Take LCD,
SP=%28432000-324000%29%2F48=%28108000%2F48%29 Divide both numerator/denominator by 2:
SP=cross%28108000%2954000%2Fcross%2848%2924
SP=54000gal%2F24hrs
Thank you,
Jojo