SOLUTION: This review will it ever end. I kinda need a refresher on solution sets and how to graph them. There are two types one is a straight equation and the other an inequality. examp

Algebra ->  Graphs -> SOLUTION: This review will it ever end. I kinda need a refresher on solution sets and how to graph them. There are two types one is a straight equation and the other an inequality. examp      Log On


   



Question 154291: This review will it ever end. I kinda need a refresher on solution sets and how to graph them. There are two types one is a straight equation and the other an inequality.
example 1. 3(2x-1)=4x+7
If its supposed to go this way I first broke it down into
6x-1=4x+7 which normally to me would become 2x=8 and x=4 but I dont think thats where that is supposed to be heading.
example 2. is 5<3w +8<14
I can sorta remember this one having to do with subtracting the 8 from the seprate sections leaving
-3<3w<6 then some sort of divison maybe?
-1< w <2
Is that how that goes or no?

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
3(2x-1)=4x+7
6x-3 = 4x+7
Subtract 4x from both sides to get:
2x - 3 = 7
Add 3 to both sides to get:
2x = 10
Divide both sides by 2 to solve for "x"
x = 5
-----------------------------
5 < 3w + 8 < 14
subtract 8 along the line:
-3 < 3w < 6
Divide thru by 3 to get:
-1 < w < 2
======================
Cheers,
Stan H.