SOLUTION: Complete the square and write the equation in standard form. Then give the center and radius of the circle x^2+y^2-2x-4y-4=0

Algebra ->  Coordinate-system -> SOLUTION: Complete the square and write the equation in standard form. Then give the center and radius of the circle x^2+y^2-2x-4y-4=0      Log On


   

Question 154246: Complete the square and write the equation in standard form. Then give the center and radius of the circle
x^2+y^2-2x-4y-4=0
Answer by orca(409) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2By%5E2-2x-4y-4=0
x%5E2%2By%5E2-2x-4y=4
x%5E2-2x%2By%5E2-4y=4
x%5E2-2x%2B1%2By%5E2-4y%2B4=4%2B1%2B4 (add 1 and 4 to both sides of the equation)
%28x%5E2-2x%2B1%29%2B%28y%5E2-4y%2B4%29=9
%28x-1%29%5E2%2B%28y-2%29%5E2=3%5E2
So
the center is (1,2),
the radius is 3