Question 154241: I need help trying to find out how to: write an equation in slope intercept form for the line that contains the given point and is perpendicular to the given line.
(2,5) , 6x+2y=24
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! I need help trying to find out how to: write an equation in slope intercept form for the line that contains the given point and is perpendicular to the given line.
(2,5) , 6x+2y=24
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Put 6x+2y=24 into slope-intercept form, y = mx + b
6x+2y=24
2y = -6x + 24
y = -3x + 12
The slope m is -3.
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A line perpendicular will have a negative inverse slope, +1/3.
So, (y - y1) = m*(x - x1)
y - 5 = (1/3)*(x - 2)
3y - 15 = x - 2
3y = x + 13
x - 3y = -13
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