SOLUTION: a person on a bike leaves an hour before a person on a motorcycle. the person on the bike is travelling at 10 mph. the person on the motorcycle is travelling at 40 mph. how long be

Click here to see ALL problems on Travel Word Problems

Question 154100: a person on a bike leaves an hour before a person on a motorcycle. the person on the bike is travelling at 10 mph. the person on the motorcycle is travelling at 40 mph. how long before the person on the motorcycle overtakes the person on the bike?
Found 2 solutions by checkley77, nerdybill:
Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website!
10(X+1)=40X
10X+10=40X
10X-40X=-10
-30X=-10
X=-10/-30
X=.33 HOURS THE MOTORCYCLE WILL OVERTAKE THE BIKER.

Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website!
a person on a bike leaves an hour before a person on a motorcycle. the person on the bike is travelling at 10 mph. the person on the motorcycle is travelling at 40 mph. how long before the person on the motorcycle overtakes the person on the bike?
.
Let t = time it takes person on motorcycle to overtake
t+1 = time person on bike traveled
.
Applying the "distance formula"
d = rt
where
d is distance
r is rate or speed
t is time
.
For motorcycle person to overtake bicycle person, the distance traveled by both must be the same:
40t = 10(t+1)
40t = 10t + 10
30t = 10
t = 10/30
t = 1/3 hour
Or, in terms of minutes:
t = 1/3 * 60 = 20 minutes