SOLUTION: What is the area in square feet of a room that is (4x-3) feet wide and (2x-7) feet long.
(4x-3)(2x-7) = 8x-28+6x-10
14x-38
------ = 7x -19
2
Algebra ->
Rectangles
-> SOLUTION: What is the area in square feet of a room that is (4x-3) feet wide and (2x-7) feet long.
(4x-3)(2x-7) = 8x-28+6x-10
14x-38
------ = 7x -19
2
Log On
Question 154084: What is the area in square feet of a room that is (4x-3) feet wide and (2x-7) feet long.
(4x-3)(2x-7) = 8x-28+6x-10
14x-38
------ = 7x -19
2 Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! Starting with:
(4x-3)(2x-7)
.
You would expand it by "FOIL" --
F -- first
O -- outer
I -- inner
L -- last
.
F: 4x*2x = 8x^2 (where ^ signifies exponentiation)
O: 4x*(-7) = -28x
I: (-3)(2x) = -6x
L: (-3)(-7) = 21
.
Combine terms:
8x^2 + (-28x) + (-6x) + 21
8x^2 + (-34x) + 21
8x^2 - 34x + 21 square feet
