SOLUTION: totally lost, I have to sketch a graph and find the vertex, x and y intercept, domain, range and the transformation I'm able to graph on calculator but that's no help to me a){{{

Algebra ->  Linear-equations -> SOLUTION: totally lost, I have to sketch a graph and find the vertex, x and y intercept, domain, range and the transformation I'm able to graph on calculator but that's no help to me a){{{      Log On


   



Question 153891: totally lost, I have to sketch a graph and find the vertex, x and y intercept, domain, range and the transformation I'm able to graph on calculator but that's no help to me
a)y=abs%28x%29
b)y=abs%282x-3%29%2B4
c)y%3C=abs%28x-2%29%2B3
Thanks any help is appreciated

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
totally lost, I have to sketch a graph and find the vertex, x and y intercept, domain, range and the transformation I'm able to graph on calculator but that's no help to me
a)y=abs%28x%29
b)y=abs%282x-3%29%2B4
c)y%3C=abs%28x-2%29%2B3
Thanks any help is appreciated

I'll do all but the last, which requires shading.

Rule:

To find the vertex of the graph of y=A%2Aabs%28Bx%2BC%29%2BD

set Bx%2BC%7D=0 and solve for x. That's the x-value of the
vertex.  The y-value of the vertex is just D.

Domain is always domain (-infinity,infinity
Range: (D,infinity) if graph opens upward  
or
Range: (-infinity),D) if graph opens downward

transformation: 
C%2FB units Right if C%2FB is negative
C%2FB units Left if  C%2FB is positive
D units Up if D is positive.
D units Down if D is negative
-----------------------

y=abs%28x%29

Consider that as: 

y=1abs%281x%2B0%29%2B0

Set 1x%2B0=0
    x=0

That is the x value of the vertex.

The y-value is 0.

So the vertex is (0,0)

Get two more points one on each side of the
vertex.

Substitute x=1

y=abs%281%29

y=1

So 1 point is (1,0)

Substitute x=-1

y=abs%28-1%29

y=1

So another point is (-1,1)

Plot those three points



Now draw a v-shaped graph with the vertex at the bottom:

 

domain: (-infinity,infinity)
range: (0,infinity)

No transformation.

-------------------


y=abs%282x-3%29%2B4

Set 2x-3=0
     2x=3
      x=3%2F2

That is the x value of the vertex.

The y-value is 4.

So the vertex is (3%2F2,4)

Get two more points one on each side of the
vertex.

Substitute x=0

y=abs%282%280%29-3%29%2B4

y=abs%280-3%29%2B4

y=abs%28-3%29%2B4

y=3%2B4

y=7

So 1 point is (0,7)

Substitute x=3

y=abs%282%283%29-3%29%2B4

y=abs%286-3%29%2B4

y=abs%283%29%2B4

y=3%2B4

y=7

So another point is (3,7)

Plot those three points



Now draw a v-shaped graph with the vertex at the bottom:


y=abs%282x-3%29%2B4

domain: (-infinity,infinity)
range: (4,infinity)
transformation: 
-3%2F2 units Right because -3%2F2 is negative
4 units Up because 4 is positive.


---------------

y%3C=abs%28x-2%29%2B3

First draw  y=abs%28x-2%29%2B3 as above, then shade all
the area below the v-shaped graph.

Edwin