SOLUTION: Please help me solve this problem: (((10a^2+22a+4))).

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Question 15383: Please help me solve this problem:
(((10a^2+22a+4))).

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
First of all, this is an EXPRESSION, NOT an EQUATION, so you can't SOLVE it. You can factor it however, and maybe that is what you wanted to do.

First factor out the common factor of 2:
2%285a%5E2+%2B+11a+%2B+2%29+

Next, arrange the first times first so there will be a 5a%5E2 in the first position. That would be 5a times a:
+2%285a+_____%29%28a+_____%29

Next, arrange so the last times last will be 2. That would have to be either 2 times 1 or 1 times 2. If you put the 1 times 2, then the outer times outer will hook up to give you 10a, and the inner times inner will be 1a, for a total of 11a, which is the middle term. So this is what works:
2%285a%2B1%29%28a%2B2%29+

R^2 at SCC

P.S. Remember, if it's NOT an equation, you can't SOLVE it!!