SOLUTION: Maximizing profit. The total profit (in dollars) for sales of x rowing machines is given by P(x)=-0.2x^2 + 300x-200. What is the profit if 500 are sold? For what value of x will th

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Question 153740: Maximizing profit. The total profit (in dollars) for sales of x rowing machines is given by P(x)=-0.2x^2 + 300x-200. What is the profit if 500 are sold? For what value of x will the profit be at a maximum?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
P%28x%29+=+-.2x%5E2+%2B+300x+-+200
Solve for x+=+500
P%28500%29+=+-+.2%2A500%5E2+%2B+300%2A500+-+200
P%28500%29+=+-.2%2A250000+%2B+150000+-+200
P%28500%29+=+-50000+%2B+150000+-+200
P%28500%29+=+99800
The profit when 500 rowing machines are sold
is $99,800
When the equation is in the form y+=+ax%5E2+%2B+bx+%2B+c,
The maximum (or minimum) occurs at x+=+%28-b%29%2F%282a%29
In this equation,
a+=+-.2
b+=+300
%28-b%29%2F%282a%29+=+%28-300%29%2F%282%2A%28-.2%29%29
%28-b%29%2F%282a%29+=+300%2F.4
%28-b%29%2F%282a%29+=+750
When 750 rowing machines are sold, the profit will be a maximum
This can be checked by looking at P%28749%29
and P%28751%29. They should both be slightly less than P%28750%29
I worked out P%28750%29 to be 112300