SOLUTION: [(2^2)(x^5)(y^-3)(z^4)/(4^0)(x^-2)(y^-8)(z^5)^3]

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Question 153637: [(2^2)(x^5)(y^-3)(z^4)/(4^0)(x^-2)(y^-8)(z^5)^3]
Answer by orca(409) About Me  (Show Source):
You can put this solution on YOUR website!
Use the formulas:
1%2Fa%5E%28-m%29=a%5Em
%28a%5Em%29%5En+=+a%5E%28mn%29
%28a%5Em%29%28a%5En%29=a%5E%28m%2Bn%29
So
%282%5E2x%5E5y%5E-3z%5E4%29%2F%284%5E0x%5E-2y%5E-8%28z%5E5%29%5E3%29
=%282%5E2x%5E5y%5E-3z%5E4%29%2F%284%5E0x%5E-2y%5E-8z%5E15%29
=%282%5E2%2F4%5E0%29x%5E5y%5E-3z%5E4x%5E2y%5E8z%5E-15
=4x%5E%285%2B2%29y%5E%28-3%2B8%29z%5E%284-15%29
=4x%5E7y%5E5z%5E-11