SOLUTION: What is the focus of the parabola with the equation (x - 1)2 + 32= 8y?

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Question 153619: What is the focus of the parabola with the equation (x - 1)2 + 32= 8y?
Answer by orca(409) About Me  (Show Source):
You can put this solution on YOUR website!
The standard form of a parabola with its axis parallel to y-axis is:
%28x-h%29%5E2=4p%28y-k%29
Its vertex is (h, k)
Its focus is (h, k+p).
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SOLUTION:
First convert the equation into the standard form.
%28x-1%29%5E2=8y-32
%28x-1%29%5E2=8%28y-4%29
%28x-1%29%5E2=4%2A2%2A%28y-4%29
So
h = 1
k = 4
p = 2
Thus its focus is (h, k+p)=(1, 6).
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%28x-1%29%5E2%2F8%2B4%29