SOLUTION: I'm really stuck on this particular question, which is: A girl buys three apples and seven oranges for $4.56 .If an orange costs $0.28 more than an apple, how much does each fruit

Algebra ->  Human-and-algebraic-language -> SOLUTION: I'm really stuck on this particular question, which is: A girl buys three apples and seven oranges for $4.56 .If an orange costs $0.28 more than an apple, how much does each fruit      Log On


   



Question 153551: I'm really stuck on this particular question, which is:
A girl buys three apples and seven oranges for $4.56 .If an orange costs $0.28 more than an apple, how much does each fruit cost?

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
I'm really stuck on this particular question, which is:
A girl buys three apples and seven oranges for $4.56 .If an orange costs $0.28 more than an apple, how much does each fruit cost?
0 solutions
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A = price of apples
R = price of oranges (O might look like a zero)
3A + 7R = 456
R = A + 28
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Substitute for R in eqn 1
3A + 7*(A+28) = 456
3A + 7A + 196 = 456
10A = 260
A = 26 cents
R = 26 + 28
R = 54 cents