SOLUTION: can you please help me decide if the following is paralles, perpendicular, or neither: (((3x+y=5 -x+3y=6)))

Algebra ->  Exponents-negative-and-fractional -> SOLUTION: can you please help me decide if the following is paralles, perpendicular, or neither: (((3x+y=5 -x+3y=6)))      Log On


   



Question 153507This question is from textbook Algebra structure and method book 1
: can you please help me decide if the following is paralles, perpendicular, or neither: (((3x+y=5 -x+3y=6))) This question is from textbook Algebra structure and method book 1

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
3x+%2B+y+=+5
-x+%2B+3y+=+6
First I want to clarify that you understand your own question
Each equation represents a straight line and you want to
know if these two line intersect ar right angles, are parallel
or intersect at some other angle
First, put both equations in the slope-intersect form which
is y+=+mx+%2B+b where m is the slope
3x+%2B+y+=+5
Subtract 3x from both sides
y+=+-3x+%2B+5
m%5B1%5D+=+-3
The other equation:
-x+%2B+3y+=+6
Add x to both sides
3y+=+x+%2B+6
Divide both sides by 3
y+=+%281%2F3%29%2Ax+%2B+2
m%5B2%5D+=+1%2F3
The slopes are perpendicular if they are related like this:
m%5B1%5D+=+-%281%2Fm%5B2%5D%29
where m%5B1%5D+=+-3 and
m%5B2%5D+=+1%2F3
The lines are perpendicular because
-3+=+-%281%2F%281%2F3%29%29