SOLUTION: (3u^2v � 2)(4u^2v + 6) this is what I got...but to be honest i'm confused a little. (3u^2v � 2)(4u^2v + 6) 12u^2v + 18u^2v 8u^2v

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Question 153238: (3u^2v � 2)(4u^2v + 6)
this is what I got...but to be honest i'm confused a little.
(3u^2v � 2)(4u^2v + 6)
12u^2v + 18u^2v
8u^2v - 12
12u^2v + 26u^2v � 12
38u^4v^2 � 12

Found 2 solutions by checkley77, jim_thompson5910:
Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website!
(3u^2v � 2)(4u^2v + 6)
3u^2v-2
4u^2v+6 now multiply
-----------------------
12u^4v^2-8u^2v+18u^2v-12 now combine like terms (-8u^2v+18u^2v).
12u^4v^2+10u^2v-12
2(6u^4v^2+5u^2v-6) answer.

Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website!

Start with the given expression.

Now let's FOIL the expression.

Remember, when you FOIL an expression, you follow this procedure:

Multiply the First terms:.

Multiply the Outer terms:.

Multiply the Inner terms:.

Multiply the Last terms:.

Now collect every term to make a single expression.

Now combine like terms.

So FOILs to .

In other words, .

SOLUTION: (3u^2v � 2)(4u^2v + 6) this is what I got...but to be honest i'm confused a little. (3u^2v � 2)(4u^2v + 6) 12u^2v + 18u^2v 8u^2v - 12 12u^2v + 26u^2v � 1