SOLUTION: Write 1024 in exponential notation Find the product of the cube of (-4/3) and square of (-3/2) Simplify [(3/4)^2 - (1/3)^3]*3^2

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Write 1024 in exponential notation Find the product of the cube of (-4/3) and square of (-3/2) Simplify [(3/4)^2 - (1/3)^3]*3^2       Log On


   

Question 153224This question is from textbook elementary and intermediate algebra
: Write 1024 in exponential notation

Find the product of the cube of (-4/3) and square of (-3/2)
Simplify [(3/4)^2 - (1/3)^3]*3^2 This question is from textbook elementary and intermediate algebra

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
2^10=1024
Find the product of the cube of (-4/3) and square of (-3/2)
(-4/3)^3*(-3/2)^2=(-2 10/27)(2 1/4)=(-54+10)/27*(8+1)/4=-44/27*9/4=-11/3
[(3/4)^2-(1/3)^3]*3^2
[9/16-1/27]*9
(227/432)*9=227/48 or 4 35/48.