SOLUTION: how do you solve y= 1/3x - 3 and y= -2x + 4 algebraically? this is the question; Solve the above system of equations algebraically, use the elimination or substitution method

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Question 153208: how do you solve y= 1/3x - 3 and y= -2x + 4 algebraically?
this is the question;
Solve the above system of equations algebraically, use the elimination or substitution method.
PLEASE HELP!!!!
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
y=+%281%2F3%29x+-+3 Start with the first equation.


+-2x+%2B+4=+%281%2F3%29x+-+3 Plug in y=+-2x+%2B+4


3%28-2x%2B4%29=3%28%281%2Fcross%283%29%29x-3%29 Multiply both sides by the LCD 3 to clear any fractions.


-6x%2B12=x-9 Distribute and multiply.


-6x=x-9-12 Subtract 12 from both sides.


-6x-x=-9-12 Subtract x from both sides.


-7x=-9-12 Combine like terms on the left side.


-7x=-21 Combine like terms on the right side.


x=%28-21%29%2F%28-7%29 Divide both sides by -7 to isolate x.


x=3 Reduce. This is the first part of our answer.


y=+-2x+%2B+4 Move onto the second equation


y=+-2%283%29+%2B+4 Plug in x=3


y=+-2 Simplify. This is the second part of our answer.


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Answer:

So the solutions are x=3 and y=+-2 which form the ordered pair (3,-2)