SOLUTION: Making a round trip from Fairview to Casterville, a distance of 20 miles, a pilot faces a 30mph head wind one way and a 30mph tail wind on the return trip. The return trip takes 4
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Question 153165: Making a round trip from Fairview to Casterville, a distance of 20 miles, a pilot faces a 30mph head wind one way and a 30mph tail wind on the return trip. The return trip takes 45 minutes less than the outbound journey. Find the speed of the plane in still air
from Fair/Cast distance=10miles; rate = (r-30); time = t
from Cast/Fair distnace= 10miles; rate = (r+30); time = t -45
the total distance is 20 miles
so 10 = t(r-30)
10 = (r+30)(t-45)
the two variables are throwing me off, somethings wrong in my setup??
Thanks for your help. Answer by orca(409) (Show Source):
You can put this solution on YOUR website! There is only a small mistake in the second equation. It is the unit of time.
Note that the unit for the speed of the wind is miles/hour. So you need to convert 45 minutes into 3/4 hours
So the simultaneous equations become:
10 = t(r-30) ................(1)
10 = (r+30)(t-3/4) ...........(2)
From equation (1), we have
Substituting it into equation (2), we have
Solving for the above equation, we obtain Multiplying both sides by 4(r-30)
(