SOLUTION: logbM = logaM/logaB is an expression of the change of base property.
a. ‘a’
b. M over b
c. M – b
d. None of the above; you have to know what b, M, and ‘a’ are first
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-> SOLUTION: logbM = logaM/logaB is an expression of the change of base property.
a. ‘a’
b. M over b
c. M – b
d. None of the above; you have to know what b, M, and ‘a’ are first
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Question 152879: logbM = logaM/logaB is an expression of the change of base property.
a. ‘a’
b. M over b
c. M – b
d. None of the above; you have to know what b, M, and ‘a’ are first Answer by jim_thompson5910(35256) (Show Source):
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