SOLUTION: The relative density of an object may be defined as its weight in air Wa, divided by the difference of its weight in air and its weight when submerged in water, Ww. For a lead wei

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Question 152839This question is from textbook basic technical mathematics with calculus
: The relative density of an object may be defined as its weight in air Wa, divided by the difference of its weight in air and its weight when submerged in water, Ww. For a lead weight, Wa = 1.097 Ww. Find the relative density of lead. This question is from textbook basic technical mathematics with calculus

Answer by mducky2(62) About Me  (Show Source):
You can put this solution on YOUR website!
This problem asks for two things:

Firstly, we need to set up the relative density equation. It says that the relative density is Wa divided by the difference of Wa and Ww, so:
W%5Ba%5D+%2F+%28W%5Ba%5D+-+W%5Bw%5D%29

Secondly, we need find the relative density of lead. Since we don't know the exact values of the lead's weight in air or the lead's weight in water, we'll just use what we know:
W%5Ba%5D+=+1.097+W%5Bw%5D

Plug this back into the relative density equation:
W%5Ba%5D+%2F+%28W%5Ba%5D+-+W%5Bw%5D%29
1.097%2AW%5Bw%5D+%2F+%281.097%2AW%5Bw%5D+-+W%5Bw%5D%29%29
1.097%2AW%5Bw%5D+%2F+%28%281.097-1%29%2AW%5Bw%5D%29%29
1.097%2AW%5Bw%5D+%2F+%28%280.097%29%2AW%5Bw%5D%29%29

They do cancel out:
1.097%2Across%28W%5Bw%5D%29+%2F+%28%280.097%29%2Across%28W%5Bw%5D%29%29
1.097+%2F+0.097
11.3092784

Therefore, the relative density of lead is 11.309.