SOLUTION: Given the functions: f(x)= {(3,5), (2,4), (1,7)} h(x)= {(3,2), (4,3), (1,6)} g(x)= sqrt(x-3) k(x)= x^2=5 determine 1) f(h(3)) 2) g(k(x)) 3) g(k(7)) 4) k(g(x))

Algebra ->  Functions -> SOLUTION: Given the functions: f(x)= {(3,5), (2,4), (1,7)} h(x)= {(3,2), (4,3), (1,6)} g(x)= sqrt(x-3) k(x)= x^2=5 determine 1) f(h(3)) 2) g(k(x)) 3) g(k(7)) 4) k(g(x))       Log On


   

Question 152544: Given the functions:
f(x)= {(3,5), (2,4), (1,7)}
h(x)= {(3,2), (4,3), (1,6)}
g(x)= sqrt(x-3)
k(x)= x^2=5
determine
1) f(h(3))
2) g(k(x))
3) g(k(7))
4) k(g(x))


Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
1) h%283%29=2
f%28h%283%29%29=f%282%29=4
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2)k%28x%29=x%5E2-5
g%28x%29=+sqrt%28x-3%29
g%28k%28x%29%29=+sqrt%28%28x%5E2-5%29-3%29
g%28k%28x%29%29=+sqrt%28x%5E2-8%29
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.
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3) From 2, g%28k%28x%29%29=+sqrt%28x%5E2-8%29
g%28k%287%29%29=+sqrt%287%5E2-8%29
g%28k%287%29%29=+sqrt%2849-8%29
g%28k%287%29%29=+sqrt%2841%29
.
.
.
4)g%28x%29=sqrt%28x-3%29
k%28x%29=x%5E2-5
k%28g%28x%29%29=%28sqrt%28x-3%29%29%5E2-5
k%28g%28x%29%29=%28x-3%29-5
k%28g%28x%29%29=x-8