SOLUTION: . How many pints of a 9% cleaning solution must be mixed with 10 pints of a 13% cleaning solution to give a 11% solution?
Algebra
->
Percentage-and-ratio-word-problems
-> SOLUTION: . How many pints of a 9% cleaning solution must be mixed with 10 pints of a 13% cleaning solution to give a 11% solution?
Log On
Word Problems: Problems on percentages, ratios, and fractions
Word
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Percentage-and-ratio-word-problems
Question 152496
:
. How many pints of a 9% cleaning solution must be mixed with 10 pints of a 13%
cleaning solution to give a 11% solution?
Answer by
mangopeeler07(462)
(
Show Source
):
You can
put this solution on YOUR website!
x=pints of 9%
coefficient=percent
9x+13(10)=11(10+x)
Distribute
9x+130=110+11x
Subtract 9x from both sides
130=110+2x
Subtract 110 from both sides
20=2x
Divide both sides by 2
10=x
x=pints of 9%
------------------------------------------------------------------------------
Answer: 10 pints of 9%