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| Question 152434:  A woman deposits $50,000 in a savings account with 4% continuously compounded interest. How many years must she wait until the balance has doubled?
 Answer by orca(409)
      (Show Source): 
You can put this solution on YOUR website! Suppose her money will be doubled at the end of n years. At the end of n years she will have 50,000(1 + 4%)^n.
 Set it equal to 2*50,000, we have
 50,000(1 + 4%)^n = 2*50,000
 Dividing both sides by 50,000, we have
 (1 + 4%)^n = 2
 1.04^n = 2
 n = log2/log1.04 = 17.7
 So she need to wait 18 years.
 
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