SOLUTION: I'm drowning in Logs & Inverses: My question states:
Determine if this is a one-to-one. If yes, find the formula for the inverse.
f(x) = (5x+4)/(7x+6)
I have listed it as
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: I'm drowning in Logs & Inverses: My question states:
Determine if this is a one-to-one. If yes, find the formula for the inverse.
f(x) = (5x+4)/(7x+6)
I have listed it as
Log On
Question 152190: I'm drowning in Logs & Inverses: My question states:
Determine if this is a one-to-one. If yes, find the formula for the inverse.
f(x) = (5x+4)/(7x+6)
I have listed it as a one-to-one and have written the following:
Changed f(x) to "y"
y =(5x+4)/(7x+6)
Then substituted "x" for "y" to get
x = (5y+4)/(7y+6)
My problem is that I don't know how to write the inverse.
Please help. Answer by scott8148(6628) (Show Source):
